【題目】請(qǐng)你利用圖中所提供的3個(gè)數(shù)據(jù),自擬一道有關(guān)化學(xué)方程式的計(jì)算題,并寫出解答過(guò)程.

【答案】自擬試題:要制得56kg含雜質(zhì)3%的生鐵需要含F(xiàn)e2O3 80%的赤鐵礦石多少千克?(或多少千克含Fe2O3 80%的赤鐵礦石,可以煉出56kg含雜質(zhì)3%的生鐵?)

解:設(shè)需要含Fe2O3 80%的赤鐵礦石的質(zhì)量為x.

Fe2O3+3CO2Fe+3CO2

160 112

x×80% 56kg×(1-3%)

160︰112=(x×80%)︰[56kg×(1-3%)] x=97kg

答:要制得56kg含雜質(zhì)3%的生鐵需要含F(xiàn)e2O3 80%的赤鐵礦石97kg.

【解析】解:設(shè)需要含Fe2O3 80%的赤鐵礦石的質(zhì)量為x.

Fe2O3+3CO2Fe+3CO2

160 112

x×80% 56kg×(1-3%)

160︰112=(x×80%)︰[56kg×(1-3%)] x=97kg

答:要制得56kg含雜質(zhì)3%的生鐵需要含F(xiàn)e2O3 80%的赤鐵礦石97kg

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