Question

1mL 98%的濃硫酸（密度為1.84g?cm^-3）跟5mL水混合，所得稀硫酸溶液溶質(zhì)的質(zhì)量分?jǐn)?shù)為

 

．

Answer 1

分析：根據(jù)溶質(zhì)質(zhì)量分?jǐn)?shù)公式進(jìn)行計(jì)算，溶質(zhì)質(zhì)量分?jǐn)?shù)為溶質(zhì)質(zhì)量與溶液質(zhì)量的比值，要將題目中的體積轉(zhuǎn)化為質(zhì)量．

解答：解：稀硫酸溶液溶質(zhì)的質(zhì)量分?jǐn)?shù)為：

1.84g/mL×1mL

1.84g/mL×1mL+1g/mL×5mL

×100%=26.4%，所以本題答案為：26.4%．

點(diǎn)評(píng)：本題考查了溶質(zhì)質(zhì)量分?jǐn)?shù)的有關(guān)計(jì)算，完成此題，可以依據(jù)溶質(zhì)質(zhì)量分?jǐn)?shù)公式進(jìn)行，要注意將體積轉(zhuǎn)化為質(zhì)量進(jìn)行計(jì)算．