BC
分析:分析溶液改變后溶液組成的改變,利用溶質(zhì)質(zhì)量分數(shù)的計算公式,計算出所得溶液的溶質(zhì)質(zhì)量分數(shù).
解答:A、將溶劑蒸發(fā)掉一半,溶質(zhì)質(zhì)量不變,仍為40g×5%=2g;蒸發(fā)后溶液中溶劑質(zhì)量=
=19g;則所得溶液的溶質(zhì)質(zhì)量分數(shù)=
×100%≈9.5%
B、加入40g15%的NaCl溶液,所得溶液的溶質(zhì)質(zhì)量分數(shù)=
×100%=10%
C、將溶液質(zhì)量蒸發(fā)掉一半,所得溶液的溶質(zhì)質(zhì)量分數(shù)=
×100%=10%
D、加入2gNaCl固體,所得溶液的溶質(zhì)質(zhì)量分數(shù)=
×100%≈9.5%
故選BC
點評:要使溶液的溶質(zhì)質(zhì)量分數(shù)增加一倍,可采取蒸發(fā)相當(dāng)于原溶液質(zhì)量一半的溶劑的質(zhì)量.