x
x-y
y2
x+y
-
x4y
x4-y4
÷
x2
x2+y2
原式=
xy2
(x-y)(x+y)
-
x4y
(x2+y2)(x2-y2)
×
x2+y2
x2

=
xy2
(x-y)(x+y)
-
x2y
(x-y)(x+y)
=
xy2-x2y
(x-y)(x+y)
=
xy(y-x)
(x-y)(x+y)
=-
xy
x+y

故答案為-
xy
x+y
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