Question

如圖所示，△ABE與△ACD全等，∠D與∠E對(duì)應(yīng)，頂點(diǎn)C與B對(duì)應(yīng)，寫出其他對(duì)應(yīng)角及對(duì)應(yīng)頂點(diǎn)．

Answer 1

答案：
解析：

解：△ABE≌△ACD，∠D與∠E對(duì)應(yīng)，因此頂點(diǎn)D與E對(duì)應(yīng)，頂點(diǎn)C與B對(duì)應(yīng)，所以A與A對(duì)應(yīng)，則∠C與∠B對(duì)應(yīng)，∠BAE與∠CAD對(duì)應(yīng)． 　　分析：在兩個(gè)全等三角形中尋找對(duì)應(yīng)元素的方法． 　　(1)根據(jù)全等關(guān)系式，如△ABE與△ACD全等，則A與A，B與C，E與D分別對(duì)應(yīng)，從而進(jìn)一步確定對(duì)應(yīng)邊及對(duì)應(yīng)角． 　　(2)根據(jù)圖形，對(duì)應(yīng)邊的夾角為對(duì)應(yīng)角，對(duì)應(yīng)角的對(duì)邊是對(duì)應(yīng)邊，兩對(duì)對(duì)應(yīng)角所夾的邊為對(duì)應(yīng)邊．另外，應(yīng)注意觀察，根據(jù)具體情況，針對(duì)兩個(gè)三角形的不同位置關(guān)系，總結(jié)找出對(duì)應(yīng)邊與對(duì)應(yīng)角的規(guī)律：①有公共邊的，公共邊一定是對(duì)應(yīng)邊；②有公共角的，公共角一定是對(duì)應(yīng)角；③有對(duì)頂角的，對(duì)頂角一定是對(duì)應(yīng)角；④一對(duì)最短(長(zhǎng))的邊一定是對(duì)應(yīng)邊；⑤一對(duì)最大(小)的角一定是對(duì)應(yīng)角．