A 分析:列舉出所有情況,看出現(xiàn)數(shù)字之積為奇數(shù)的情況數(shù)占所有情況數(shù)的多少即可. 解答:列表得:(1,6)(2,6)(3,6)(4,6)(5,6)(6,6)(1,5)(2,5)(3,5)(4,5)(5,5)(6,5)(1,4)(2,4)(3,4)(4,4)(5,4)(6,4)(1,3)(2,3)(3,3)(4,3)(5,3)(6,3)(1,2)(2,2)(3,2)(4,2)(5,2)(6,2)(1,1)(2,1)(3,1)(4,1)(5,1)(6,1)共有36種情況,數(shù)字之積為奇數(shù)的有9種情況,所以概率為:, 故選A. 點評:此題考查了用列表格的方法解決概率問題;得到數(shù)字之積為奇數(shù)的情況數(shù)是解決本題的關(guān)鍵;用到的知識點為:概率等于所求情況數(shù)與總情況數(shù)之比.