解:(1)去括號(hào)得,4x+2=x+7
移項(xiàng)合并同類項(xiàng)得,3x=5
系數(shù)化1得,
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;
(2)去括號(hào)得:3-6x-4=
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∴
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;
(3)去分母得,4(1-y)-12y=36-3(y+2)
去括號(hào)得,4-16y=30-3y
移項(xiàng)合并同類項(xiàng)得,-13y=26
系數(shù)化1得,y=-2;
(4)去分母得,15x-10-
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x=15
移項(xiàng)合并同類項(xiàng)得,
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.
分析:(1)此題主要是去括號(hào),合并同類,移項(xiàng);
(2)此題主要是去括號(hào),合并同類項(xiàng),移項(xiàng);
(3)等式兩邊同乘12,去分母,再去括號(hào),移項(xiàng)合并即可;
(4)等式兩邊同乘30去分母,再去括號(hào),移項(xiàng)合并即可.
點(diǎn)評(píng):規(guī)律總結(jié):一元一次方程的解法:一般要通過(guò)去分母,去括號(hào),移項(xiàng),合并同類項(xiàng),未知數(shù)的系數(shù)化為1等步驟,把一個(gè)一元一次方程“轉(zhuǎn)化”成x=a的形式.解題時(shí),要靈活運(yùn)用這些步驟.