解答:解:N2H4(g)+O2(g)=N2(g)+2H2O(g)△H1=-533.23kJ?mol-1 ① H2O(g)=H2O (l)△H2=-44kJ?mol-1 ② 2H2O2(l)=2H2O(l)+O2(g)△H3=-196.4kJ?mol-1 ③ 則聯(lián)氨與過氧化氫反應(yīng)的熱化學(xué)方程式可用①+②×2+③:N2H4(g)+2H2O2(l)=N2(g)+4H2O(l)△H=-817.63kJ?mol-1 或用①-②×2+③:N2H4(g)+2H2O2(l)=N2(g)+4H2O(l)△H=-641.63kJ?mol-1, 故選B.