(理)將圓x2+y2=1按向量a=(2,-1)平移后,恰好與直線x-y+b=0相切,則實(shí)數(shù)b的值為

A.3±            B.-3±            C.2±            D.-2±

答案:(理)B  圓x2+y2=1,按a=(2,-1)平移后為(x-2)2+(y+1)2=1與x-y+b=0相切.

=1,|b+3|=,b=-3±.∴選B.

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