已知函數(shù)y=logax(0<a≠1)的反函數(shù)y=f-1(x),給出關(guān)于f(x)與f-1(x)的四個(gè)命題:其中正確命題的序號(hào)是________.
①兩個(gè)函數(shù)必有相同的單調(diào)性;
②當(dāng)a>1時(shí),兩個(gè)函數(shù)的圖象沒有交點(diǎn);
③若兩個(gè)函數(shù)的圖象有交點(diǎn),交點(diǎn)一定在y=x上;
④兩個(gè)函數(shù)圖象有交點(diǎn)的充分不必要條件為0<a<1.
①②③
分析:根據(jù)指數(shù)函數(shù)和同底的對(duì)數(shù)函數(shù)的單調(diào)性與底數(shù)的關(guān)系,可以判斷①的真假;根據(jù)a>1時(shí),數(shù)函數(shù)和同底的對(duì)數(shù)函數(shù)的圖象,可以判斷②的真假;根據(jù)當(dāng)0<a<1時(shí),數(shù)函數(shù)和同底的對(duì)數(shù)函數(shù)的圖象,可以判斷③的真假;根據(jù)③中結(jié)論,結(jié)合充要條件的定義,可以判斷④的真假;進(jìn)而得到答案.
解答:∵函數(shù)y=logax(0<a≠1)的反函數(shù)y=f-1(x)=ax,
∴當(dāng)a>1時(shí),原函數(shù)和反函數(shù)均為增函數(shù),當(dāng)0<a<1時(shí),原函數(shù)和反函數(shù)均為減函數(shù),
故①兩個(gè)函數(shù)必有相同的單調(diào)性正確;
當(dāng)a>1時(shí),函數(shù)y=logax(0<a≠1)與函數(shù)y=ax的圖象分別位置直線y=x兩側(cè),
故兩個(gè)函數(shù)的圖象沒有交點(diǎn),故②正確;
當(dāng)0<a<1時(shí),函數(shù)y=logax(0<a≠1)與函數(shù)y=ax的圖象交于直線y=x上一點(diǎn)
故③若兩個(gè)函數(shù)的圖象有交點(diǎn),交點(diǎn)一定在y=x上正確;
兩個(gè)函數(shù)圖象有交點(diǎn)的充要條件為0<a<1,故④錯(cuò)誤
故答案為:①②③
點(diǎn)評(píng):本題考查的知識(shí)點(diǎn)是反函數(shù),指數(shù)函數(shù)和對(duì)數(shù)函數(shù)的圖象和性質(zhì),其中熟練掌握同底的指數(shù)和對(duì)數(shù)函數(shù)的圖象和性質(zhì)是解答本題的關(guān)鍵.