實數(shù)x,y滿足x2=2xsin(xy)-1,則x2010+6sin5y=________.
7
分析:由(x-sin(xy))2+cos2(xy)=0,知x=sin(xy),且cos(xy)=0,所以x=sin(xy)=±1.由此能求出x2010+6sin5y.
解答:(x-sin(xy))2+cos2(xy)=0
∴x=sin(xy) 且 cos(xy)=0
∴x=sin(xy)=±1
∴siny=1 xsin(xy)=1
x2010+6sin5y=7.
故答案為:7.
點評:本題考查函數(shù)的值的求法,解題時要認真審題,仔細解答,注意三角函數(shù)性質的靈活運用.