已知(1＋x)＋(1＋x)²＋(1＋x)³＋…＋(1＋x)⁸＝a₀＋a₁x＋a₂x²＋…＋a₈x⁸，則a₁＋a₂＋a₃＋…＋a₈＝________.

1－90C₁₀¹＋90²C₁₀²－90³C₁₀³＋…＋(－1)^k90^kC₁₀^k＋…＋90¹⁰C₁₀¹⁰除以88的余數(shù)是________．

(2－)⁸展開式中不含x⁴項(xiàng)的系數(shù)的和為________．

若(1＋5x²)ⁿ的展開式中各項(xiàng)系數(shù)之和是a_n，(2x³＋5)ⁿ的展開式中各項(xiàng)的二項(xiàng)式系數(shù)之和為b_n，則的值為________．

1＋3＋3²＋…＋3⁹⁹被4除，所得的余數(shù)為________．

已知ⁿ的二項(xiàng)展開式的各項(xiàng)系數(shù)和為32，則二項(xiàng)展開式中x的系數(shù)為________．

若(3x－1)⁷＝a₇x⁷＋a₆x⁶＋…＋a₁x＋a₀，則a₇＋a₆＋…＋a₁＝________.

(1－)⁴(1＋)⁴的展開式中x項(xiàng)的系數(shù)是________．

設(shè)f(x)＝(2x＋1)⁵－5(2x＋1)⁴＋10(2x＋1)³－10(2x＋1)²＋5(2x＋1)－1，則f(x)＝________.

(1＋2x²)⁸的展開式中的常數(shù)項(xiàng)為________．