(1)C6H12O6(s)+6O2(g)===6CO2(g)+6H2O(l); ΔH= -2800 kJ·mol-1 (2) 2800 kJ·mol-1×100g/180g·mol-1=1556 kJ 課后練習: 1B 2D 3D 4D 5A 查看更多

 

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人體內(nèi)葡萄糖的消耗為:

C6H12O6(s)(葡萄糖)+6O2(g)6CO2(g)+6H2O(l) ΔH=-2800 kJ·mol-1,如果某人每天消耗12540 kJ的熱量,則他每天至少要攝入葡萄糖的質(zhì)量為

[  ]

A.

806 g

B.

1000 g

C.

1250 g

D.

1 500 g

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25℃、101 kPa下,碳、氫氣、甲烷和葡萄糖的燃燒熱依次是393.5 kJ/mol、285.8 kJ/mol、890.3 kJ/mol、2800 kJ/mol,則下列熱化學方程式正確的是(    )

A.C(s)+1/2 O2(g)=CO(g)                     △H= ―393.5 kJ/mol

B.2H2(g)+O2(g)=2H2O(l)                   △H=  +571.6 kJ/mol

C.CH4(g)+2O2(g)=CO2(g)+2H2O(g)           △H= ―890.3 kJ/mol

D.C6H12O6(s) +6O2(g)=6CO2(g)+6H2O(l)      △H= ―2800 kJ/mol

 

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25℃、101 kPa下,碳、氫氣、甲烷和葡萄糖的燃燒熱依次是393.5 kJ/mol、285.8 kJ/mol、890.3 kJ/mol、2800 kJ/mol,則下列熱化學方程式正確的是(   )

A.C(s)+1/2 O2(g)=CO(g)△H=" ―393.5" kJ/mol
B.2H2(g)+O2(g)=2H2O(l)△H="" +571.6 kJ/mol
C.CH4(g)+2O2(g)=CO2(g)+2H2O(g)△H=" ―890.3" kJ/mol
D.C6H12O6(s) +6O2(g)=6CO2(g)+6H2O(l)△H=" ―2800" kJ/mol

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25℃、101 kPa下,碳、氫氣、甲烷和葡萄糖的燃燒熱依次是393.5 kJ/mol、285.8 kJ/mol、890.3 kJ/mol、2800 kJ/mol,則下列熱化學方程式正確的是

A.C(s)+1/2O2(g)=CO(g) △H =" -" 393.5 kJ/mol
B.2H2(g)+O2(g)=2H2O(l) △H =" +" 571.6 kJ/mol
C.CH4(g)+2O2(g)=CO2(g)+2H2O(g) △H =" -" 890.3 kJ/mol
D.C6H12O6(s) +6O2(g)=6CO2(g)+6H2O(l) △H =" -" 2800 kJ/mol

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25℃、101 kPa下,碳、氫氣、甲烷和葡萄糖的燃燒熱依次是393.5 kJ/mol、285.8 kJ/mol、890.3 kJ/mol、2800 kJ/mol,則下列熱化學方程式正確的是

A.C(s)+1/2O2(g)=CO(g)                    △H = - 393.5 kJ/mol

B.2H2(g)+O2(g)=2H2O(l)                  △H = + 571.6 kJ/mol

C.CH4(g)+2O2(g)=CO2(g)+2H2O(g)          △H = - 890.3 kJ/mol

D.C6H12O6(s) +6O2(g)=6CO2(g)+6H2O(l)     △H = - 2800 kJ/mol

 

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