題目列表(包括答案和解析)
人體內(nèi)葡萄糖的消耗為: C6H12O6(s)(葡萄糖)+6O2(g)6CO2(g)+6H2O(l) ΔH=-2800 kJ·mol-1,如果某人每天消耗12540 kJ的熱量,則他每天至少要攝入葡萄糖的質(zhì)量為 | |
[ ] | |
A. |
806 g |
B. |
1000 g |
C. |
1250 g |
D. |
1 500 g |
25℃、101 kPa下,碳、氫氣、甲烷和葡萄糖的燃燒熱依次是393.5 kJ/mol、285.8 kJ/mol、890.3 kJ/mol、2800 kJ/mol,則下列熱化學方程式正確的是( )
A.C(s)+1/2 O2(g)=CO(g) △H= ―393.5 kJ/mol
B.2H2(g)+O2(g)=2H2O(l) △H= +571.6 kJ/mol
C.CH4(g)+2O2(g)=CO2(g)+2H2O(g) △H= ―890.3 kJ/mol
D.C6H12O6(s) +6O2(g)=6CO2(g)+6H2O(l) △H= ―2800 kJ/mol
25℃、101 kPa下,碳、氫氣、甲烷和葡萄糖的燃燒熱依次是393.5 kJ/mol、285.8 kJ/mol、890.3 kJ/mol、2800 kJ/mol,則下列熱化學方程式正確的是( )
A.C(s)+1/2 O2(g)=CO(g)△H=" ―393.5" kJ/mol |
B.2H2(g)+O2(g)=2H2O(l)△H="" +571.6 kJ/mol |
C.CH4(g)+2O2(g)=CO2(g)+2H2O(g)△H=" ―890.3" kJ/mol |
D.C6H12O6(s) +6O2(g)=6CO2(g)+6H2O(l)△H=" ―2800" kJ/mol |
25℃、101 kPa下,碳、氫氣、甲烷和葡萄糖的燃燒熱依次是393.5 kJ/mol、285.8 kJ/mol、890.3 kJ/mol、2800 kJ/mol,則下列熱化學方程式正確的是
A.C(s)+1/2O2(g)=CO(g) △H =" -" 393.5 kJ/mol |
B.2H2(g)+O2(g)=2H2O(l) △H =" +" 571.6 kJ/mol |
C.CH4(g)+2O2(g)=CO2(g)+2H2O(g) △H =" -" 890.3 kJ/mol |
D.C6H12O6(s) +6O2(g)=6CO2(g)+6H2O(l) △H =" -" 2800 kJ/mol |
25℃、101 kPa下,碳、氫氣、甲烷和葡萄糖的燃燒熱依次是393.5 kJ/mol、285.8 kJ/mol、890.3 kJ/mol、2800 kJ/mol,則下列熱化學方程式正確的是
A.C(s)+1/2O2(g)=CO(g) △H = - 393.5 kJ/mol
B.2H2(g)+O2(g)=2H2O(l) △H = + 571.6 kJ/mol
C.CH4(g)+2O2(g)=CO2(g)+2H2O(g) △H = - 890.3 kJ/mol
D.C6H12O6(s) +6O2(g)=6CO2(g)+6H2O(l) △H = - 2800 kJ/mol
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