(西南師大附中高2009級第三次月考)已知 (1)若p > 1時(shí).解關(guān)于x的不等式, (2)若對時(shí)恒成立.求p的范圍. 解:(1) ······················································································ 1分 ①········································ 3分 ② p = 2時(shí).解集為····················································· 5分 ③ p > 2時(shí).解集為··········································· 7分 (2) ··········································································· 8分 ∴ 恒成立 ∴ 恒成立······································ 9分 ∵ 上遞減·················································· 10分 ∴ ················································································ 11分 ∴ p > 2 ·································································································· 12分 查看更多

 

題目列表(包括答案和解析)

(08年東北師大附中文)(12分)

已知等差數(shù)列,,公差,且, ,成等比數(shù)列,

(Ⅰ)求的通項(xiàng)公式;

(Ⅱ)設(shè)的前項(xiàng)和為,求證:

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.師大附中青華校區(qū)從三樓半到四樓共有11級臺階,某老師一步可以上一級、二級或三

    級臺階,若步上完,共有                    種不同方法.(用數(shù)字作答)

 

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(08年哈師大附中文) 過拋物線的焦點(diǎn)作一條直線與拋物線相交于兩點(diǎn),且,則這樣的直線有

   A.一條    B.兩條    C.三條    D.不存在

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(08年哈師大附中文)為了解某校高三學(xué)生的視力情況,隨機(jī)地抽查了該校100名高三學(xué)生的視力情況,得到頻率分布直方圖(如右圖),由于不慎將部分?jǐn)?shù)據(jù)丟失,但知道前4組頻數(shù)成等比數(shù)列,后6組的頻數(shù)成等差數(shù)列,若最大頻率為a,視力在4.6到5.0之間的學(xué)生數(shù)為b,則a、b的值分別為

A.0.27和78        B.0.09和75           C.0.22和58             D.0.27和75

 

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(08年東北師大附中文) 已知,則下列不等式成立的是

(A)

(B)

(C)

(D)

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