解:(1)355+260+140+245
=(355+245)+(260+140)
=600+400,
=1000;
(2)98×101
=90×(100+1),
=90×100+98,
=9000+98,
=9098;
(3)48×125
=6×(8×125),
=6×1000,
=6000;
(4)645-180-245
=645-245-180,
=400-180,
=220;
(5)38×99+38
=(99+1)×38,
=100×38,
=3800;
(6)3500÷14÷5
=3500÷(14×5),
=3500÷70,
=50;
(7)175×56+25×56
=(175+25)×56,
=200×56,
=11200;
(8)50×25×20×40
=50×20×(25×40),
=1000×1000,
=1000000.
分析:(1)可根據(jù)加法交換律及結(jié)合律計算;
(2)可將101拆分為100+1后根據(jù)乘法分配律計算;
(3)可將48變?yōu)?×8后根據(jù)乘法結(jié)合律計算;
(4)可根據(jù)交換律計算;
(5)(7)可根據(jù)乘法分配律計算;
(6)可根據(jù)一個數(shù)除以兩個數(shù),等于用這個數(shù)除以這兩個數(shù)的積的除法性質(zhì)計算;
(8)可根據(jù)乘法交換律及結(jié)合律計算.
點評:完成本題要注意分析式中數(shù)據(jù)的特點,然后運用合適的方法計算.