∠1+∠2+∠3=180°,其中∠1=52°,∠2=46°,那么∠3=
82°
82°
分析:由于∠1+∠2+∠3=180°,可知∠3=180°-∠1-∠2,將∠1=52°,∠2=46°代入計(jì)算即可求解.
解答:解:∠3=180°-∠1-∠2,
=180°-52°-46°,
=82°.
故答案為:82°.
點(diǎn)評:考查了角的和差計(jì)算,將∠1=52°,∠2=46°代入計(jì)算即可.
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