452÷20+109×43= 101×92-92= 907×99+907=
274+299+201+326= 6.5×99+6.5= 31.25÷25×0.5=
3.8×4.2+38×0.58= 13-
7
8
+
1
8
=
1
2
+
1
3
+
1
6
)×2×3×4=
3
7
×(
4
5
-
2
3
)÷
3
15
=
36÷[(
5
6
-
2
3
)×3]=
1
8
÷(
1
4
+2.5×
4
5
)=
分析:算式(1)(6)(8)(11)(12)根據(jù)四則混合運算的運算順序計算即可:先算乘除,再算加減,有括號的要先算括號里面的;
算式(2)(3)(5)(9)(10)可根據(jù)乘法分配律計算;
算式(4)可根據(jù)加法交換律及結(jié)合律計算;
算式(7)可先將式中3.8×4.2變?yōu)?8×0.42后再根據(jù)乘法分配律計算.
解答:解:(1)452÷20+109×43
=22.6+4687,
=4709.6;

(2)101×92-92,
=(101-1)×92,
=100×92,
=9200;

(3)907×99+907,
=(99+1)×907,
=100×907,
=90700;

(4)274+299+201+326,
=(274+326)+(299+201),
=600+500,
=1100;

(5)6.5×99+6.5,
=(99+1)×6.5,
=100×6.5,
=650;

(6)31.25÷25×0.5,
=1.25÷0.5,
=2.5;

(7)3.8×4.2+38×0.58
=38×0.42+38×0.58
=(0.42+0.58)×38,
=1×0.38,
=38;

(8)13-
7
8
+
1
8

=12
1
8
+
1
8

=12
2
8
;

(9)(
1
2
+
1
3
+
1
6
)×2×3×4
=(
1
2
+
1
3
+
1
6
)×24,
=
1
2
×24+
1
3
×24+
1
6
×24,
=12+8+4,
=24;

(10)
3
7
×(
4
5
-
2
3
)÷
3
15

=
3
7
×(
4
5
×
15
3
-
2
3
×
15
3
),
=
3
7
×(
12
3
-
10
3
),
=
3
7
×
2
3
,
=
2
7
;

(11)36÷[(
5
6
-
2
3
)×3]
=36÷[
1
6
×3],
=36÷
1
2
,
=72;

(12)
1
8
÷(
1
4
+2.5×
4
5

=
1
8
÷[
1
4
+2],
=
1
8
×
4
9
,
=
1
18
點評:完成本題要細心分析式中數(shù)據(jù)的特點,選擇合適的方法進行計算.
練習冊系列答案
相關習題

科目:小學數(shù)學 來源: 題型:解答題

452÷20+109×43=101×92-92=907×99+907=
274+299+201+326=6.5×99+6.5=31.25÷25×0.5=
3.8×4.2+38×0.58=13-數(shù)學公式+數(shù)學公式=數(shù)學公式+數(shù)學公式+數(shù)學公式)×2×3×4=
數(shù)學公式×(數(shù)學公式-數(shù)學公式)÷數(shù)學公式=36÷[(數(shù)學公式-數(shù)學公式)×3]=數(shù)學公式÷(數(shù)學公式+2.5×數(shù)學公式)=

查看答案和解析>>

同步練習冊答案