細心計算.
99×
5
8
-62.5%×68+6.25×0.1;               
1
4
×39+
3
4
×25+
26
4
×
3
13
;  
1
2006
+
2
2006
+
3
2006
 …+
2005
2006
;
1
1×2
+
1
2×3
+
1
3×4
+-+
1
9×10
分析:(1)(2)通過數(shù)字轉(zhuǎn)化與變形,運用乘法分配律簡算;
(3)分母相同,只把分子相加,分子部分運用求和公式簡算即可;
(4)把每個分?jǐn)?shù)拆成兩個分?jǐn)?shù)相加的形式,然后通過加減相互抵消,求得結(jié)果.
解答:解:(1)99×
5
8
-62.5%×68+6.25×0.1
=99×0.625-0.625×68+0.625×1
=(99-68+1)×0.625
=32×0.625
=32×
5
8

=20

(2)
1
4
×39+
3
4
×25+
26
4
×
3
13

=
3
4
×13+
3
4
×25+
3
4
×2
=
3
4
×(13+25+2)
=
3
4
×40
=30

(3)
1
2006
+
2
2006
+
3
2006
 …+
2005
2006

=
1+2+3+…+2005
2006

=
(1+2005)×2005÷2
2006

=
2006×2005÷2
2006

=1002.5

(4)
1
1×2
+
1
2×3
+
1
3×4
+…+
1
9×10

=1-
1
2
+
1
2
-
1
3
+
1
3
-
1
4
+…+
1
9
-
1
10

=1-
1
10

=
9
10
點評:此題主要考查學(xué)生能否根據(jù)數(shù)字特點,通過轉(zhuǎn)化的數(shù)學(xué)思想,巧妙靈活地運用運算定律,使復(fù)雜的問題簡單化.
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