Question

10．根據(jù)規(guī)律填數(shù)．
（1）$\begin{array}{l}\frac{1}{2}\end{array}$、$\begin{array}{l}\frac{1}{3}\end{array}$、$\begin{array}{l}\frac{5}{6}\end{array}$、$\begin{array}{l}\frac{7}{6}\end{array}$、2、$\frac{19}{6}$、$\frac{31}{6}$；       
（2）$\begin{array}{l}\frac{1}{5}\end{array}$、$\begin{array}{l}\frac{2}{10}\end{array}$、$\begin{array}{l}\frac{3}{15}\end{array}$、$\frac{4}{20}$、$\frac{5}{25}$．

Answer 1

分析 （1）每個數(shù)是前面兩個數(shù)的和，據(jù)此解答；
（2）分母依次加上5，分子依次加上1，據(jù)此解答．

解答 解：$\frac{7}{6}$+2=$\frac{19}{6}$
2+$\frac{19}{6}$=$\frac{31}{6}$

（2）3+1=4
15+5=20
所以應(yīng)該是$\frac{4}{20}$
4+1=5
20+5=25
所以應(yīng)該是$\frac{5}{25}$；
故答案為：$\frac{19}{6}$，$\frac{31}{6}$，$\frac{4}{20}$，$\frac{5}{25}$．

點(diǎn)評 解答此題的關(guān)鍵是根據(jù)所給出的數(shù)列，找出規(guī)律，再根據(jù)規(guī)律解決問題．