分析:(1)運用加法交換律與結(jié)合律簡算;
(2)原式變?yōu)?5×
+3×
+2.64×12.5,即265+3×1.25+26.4×1.25,運用乘法分配律簡算;
(3)把29看作30-1,運用乘法分配律簡算;
(4)原式變?yōu)?-(
+
+
+…+
),把每個分數(shù)拆成兩個分數(shù)相減的形式,然后通過加減相抵消的方法,求出結(jié)果;
(5)通過觀察,發(fā)現(xiàn)2011-2008=3,2010-2007=3,2009-2006=3,…,共有2010÷2=1050個3,最后加上1即可.
解答:解:(1)25-
3+
8-
6,
=25-(
3+
6)+
8,
=25-10+
8,
=23
;
(2)25×
10+3÷
+2.64×12.5,
=25×
+3×
+2.64×12.5,
=265+3×1.25+26.4×1.25,
=265+(3+26.4)×1.25,
=265+36.75,
=301.75;
(3)
×119,
=
×119,
=(1-
)×119,
=119-
,
=119-3
,
=115
;
(4)1-
-
-
-…-
,
=1-(
+
+
+…+
),
=1-[(1-
)+(
-
)+(
-
)+…+(
-
)],
=1-[1-
],
=1-1+
,
=
;
(5)2011+2010+2009-2008-2007-2006+2005+…-8+7+6+5-4-3-2+1,
=(2011-2008)+(2010-2007)+(2009-2006)+(2005-2002)…+(7-4)+(6-3)+(5-2)+1,
=3+3+3+3+…+3+1,
=3×(2010÷2)+1,
=3×1005+1,
=3015+1,
=3016.
點評:此題考查了運算定律與簡便運算,四則混合運算,靈活運用所學(xué)的運算定律律或運算技巧進行簡便計算.