分析:(1)根據(jù)等式的性質(zhì),兩邊同減去35,再同除以25即可;
(2)根據(jù)等式的性質(zhì),兩邊同加上1.5x,得 0.54+1.5x=4.2,兩邊同減去0.54,再同除以1.5即可;
(3)原式變?yōu)?0+2x=24.8,兩邊同減去20,再同除以2即可.
解答:解:(1)25x+35=460,
25x+35-35=460-35,
25x=425,
25x÷25=425÷25,
x=17;
(2)4.2-1.5x=0.54,
4.2-1.5x+1.5x=0.54+1.5x,
0.54+1.5x=4.2,
0.54+1.5x-0.54=4.2-0.54,
1.5x=3.66,
1.5x÷1.5=3.66÷1.5,
x=2.44;
(3)8×2.5+2x=24.8,
20+2x=24.8,
20+2x-20=24.8-20,
2x=4.8,
2x÷2=4.8÷2,
x=2.4.
點評:在解方程時應(yīng)根據(jù)等式的性質(zhì),即等式兩邊同加上、同減去、同乘上或同除以某一個數(shù)(0除外),等式的兩邊仍相等,同時注意“=”上下要對齊.