(1)□÷□=5…2,除數(shù)最小是______,這時(shí)被除數(shù)是______.
(2)□÷□=5…4,除數(shù)最小是______,這時(shí)被除數(shù)是______.
解:(1)除數(shù)最小是:2+1=3,
3×5+2=17;
答:除數(shù)最小是3,這時(shí)被除數(shù)是17;
(2)除數(shù)最小是:4+1=5,
5×5+4=29;
答:除數(shù)最小是5,這時(shí)被除數(shù)是29;
故答案為:3,17,5,29.
分析:根據(jù)“在有余數(shù)的除法中,余數(shù)總比除數(shù)小”可知:因?yàn)橛鄶?shù)是2,除數(shù)最小是3;當(dāng)除數(shù)最小時(shí),被除數(shù)最小,根據(jù)“被除數(shù)=商×除數(shù)+余數(shù)”進(jìn)行解答即可.
點(diǎn)評:解答此題的關(guān)鍵:根據(jù)在有余數(shù)的除法中,余數(shù)總比除數(shù)小,得出除數(shù)最小為:余數(shù)+1,然后被除數(shù)、除數(shù)、商和余數(shù)四個(gè)量之間的關(guān)系進(jìn)行解答即可.