(1+0.23+0.34)×(0.23+0.34+0.56)-(1+0.23+0.34+0.56)×(0.23+0.34)
分析:通過觀察,此題中的數(shù)據(jù)很有特點(diǎn),于是根據(jù)題中數(shù)據(jù),設(shè)1+0.23+034=a,0.23+0.34=b,那么a-b=1+00.23+0.34-(0.23+0.34)=1.于是原式變?yōu)閍×(b+0.56)-(a+0.56)×b=0.56×(a-b),把a(bǔ)-b=1,代入即可求出.
解答:解:設(shè)1+0.23+034=a,0.23+0.34=b,那么a-b=1+00.23+0.34-(0.23+0.34)=1.
(1+0.23+0.34)×(0.23+0.34+0.56)-(1+0.23+0.34+0.56)×(0.23+0.34),
=a×(b+0.56)-(a+0.56)×b,
=ab+0.56a-ab-0.56b,
=0.56a-0.56b,
=0.56×(a-b),
=0.56×1,
=0.56.
點(diǎn)評:解決這類問題,應(yīng)注意審題,根據(jù)數(shù)字特點(diǎn),運(yùn)用運(yùn)算技巧,巧妙解答.
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