15
34
×51×
2
9
      
2
5
×
3
8
÷
2
5
×
3
8
      
3
4
×[1÷(
5
6
+
3
4
)]
8
31
×15+
15
31
×23       
7
9
×52+
2
9
×51.
分析:(1)按照從左往右的順序計(jì)算即可求解;
(2)將除法變?yōu)槌朔,再約分計(jì)算即可求解;
(3)先算小括號(hào)里面的加法,再算中括號(hào)里面的除法,最后計(jì)算括號(hào)外面的乘法;
(4)先將原式變形為
15
31
×8+
15
31
×23,再根據(jù)乘法分配律進(jìn)行計(jì)算;
(5)先將原式變形為
7
9
+
7
9
×51+
2
9
×51,再根據(jù)乘法分配律進(jìn)行計(jì)算.
解答:解:(1)
15
34
×51×
2
9
  
=
45
2
×
2
9
  
=5;
  
(2)
2
5
×
3
8
÷
2
5
×
3
8
 
=
2
5
×
3
8
×
5
2
×
3
8
 
=
9
64
;

(3)
3
4
×[1÷(
5
6
+
3
4
)]
=
3
4
×[1÷
19
12
]
=
3
4
×
12
19

=
9
19
;

(4)
8
31
×15+
15
31
×23
=
15
31
×8+
15
31
×23
、
15
31
×(8+23)
=
15
31
×31
=15;

(5)
7
9
×52+
2
9
×51
=
7
9
+
7
9
×51+
2
9
×51
=
7
9
+(
7
9
+
2
9
)×51
=
7
9
+1×51
=
7
9
+51
=51
7
9
點(diǎn)評(píng):考查了運(yùn)算定律與簡(jiǎn)便運(yùn)算,四則混合運(yùn)算.注意運(yùn)算順序和運(yùn)算法則,靈活運(yùn)用所學(xué)的運(yùn)算律簡(jiǎn)便計(jì)算.
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