5
7
×53+
1
7
×85.
分析:先把
5
7
×53+
1
7
×85改寫成
1
7
×265+
1
7
×85
,進而逆用乘法分配律簡算即可.
解答:解:
5
7
×53+
1
7
×85,
=
1
7
×265+
1
7
×85
,
=
1
7
×(265+85),
=
1
7
×350
,
=50.
點評:本題主要考查學生運用乘法分配律解決問題的能力,解答此題的關鍵是弄清:
5
7
×53=
1
7
×265.
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(122)3÷2.5(123)84+(54-16)(124)數(shù)學公式+數(shù)學公式+數(shù)學公式+數(shù)學公式(125)數(shù)學公式-(數(shù)學公式÷數(shù)學公式+數(shù)學公式
(126)3×(數(shù)學公式+數(shù)學公式)+數(shù)學公式(127)7.2÷(5-0.75+0.25)(128)725÷25+275÷25(129)數(shù)學公式×數(shù)學公式×數(shù)學公式
(130)數(shù)學公式×45-數(shù)學公式÷數(shù)學公式(131)48×(數(shù)學公式-數(shù)學公式(132)數(shù)學公式×數(shù)學公式+數(shù)學公式×數(shù)學公式(133)(32+數(shù)學公式)÷4
(134)數(shù)學公式÷數(shù)學公式÷數(shù)學公式(135)46×數(shù)學公式(136)數(shù)學公式×數(shù)學公式+數(shù)學公式÷9

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