分析:算式(1)可將32拆分為8×4后再根據(jù)乘法交換律及結(jié)合律進(jìn)行計(jì)算;
算式(2)可將分?jǐn)?shù)化為小數(shù)后再根據(jù)一個(gè)數(shù)減兩個(gè)數(shù)的和,等于用這個(gè)數(shù)分別減去這兩個(gè)數(shù)的減法性質(zhì)及加法交換律進(jìn)行計(jì)算;
算式(3)可根據(jù)乘法分配律進(jìn)行計(jì)算.
解答:解:(1)25×1.25×32
=25×1.25×8×4,
=(25×4)×(1.25×8),
=100×10,
=1000;
(2)17.625-(4.4+7
)
=17.625-4.4-7.625,
=17.625-7.625-4.4,
=10-4.4,
=5.6;
(3)(
+
)×15×17
=
×15×17+
×15×17,
=17+30,
=47.
點(diǎn)評(píng):當(dāng)算式中同時(shí)含有分?jǐn)?shù)與小數(shù)時(shí),要根據(jù)式中數(shù)據(jù)的特點(diǎn),將分?jǐn)?shù)化為小數(shù)或?qū)⑿?shù)化為分?jǐn)?shù)后再進(jìn)行計(jì)算.