(1)
(+-)×(-12);
(2)-|-3
2|÷3×(-
)-(-2)
3;
(3)(-2)
2011+(-2)
2012;
(4)2(a
2b-2ab
2+c)-(2c+3a
2b-ab
2).
(1)原式=(-12)×
+(-12)×
-(-12)×
=-5-8+9
=-4;
(2)原式=-9×
×(-
)-(-8)
=1+8
=9;
(3)原式=(-2)
2011+(-2)
2011×(-2)
=(1-2)×(-2)
2011
=(-1)×(-2
2011)
=-2
2011;
(4)原式=2a
2b-4ab
2+2c-2c-3a
2b+ab
2
=-a
2b-3ab
2
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