Question

如圖14，△ABC是等腰直角三角形，BC是斜邊，P為△ABC內(nèi)一點(diǎn)，將△ABP繞點(diǎn)A逆時(shí)針旋轉(zhuǎn)后與△ACP 重合，如果AP=3，那么線段P P的長(zhǎng)是多少？                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                             

 

Answer 1

 解：根據(jù)旋轉(zhuǎn)的性質(zhì)可知將△ABP繞點(diǎn)A逆時(shí)針旋轉(zhuǎn)后與

  △ACP 重合△ABP≌△ACP,所以AP=A P,∠BAC=∠PA P=90°.所以在Rt△AP P

  中，P P=.