已知函數(shù)f(x)=ax
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+(1-3a)x+a在區(qū)間
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上遞增,則實數(shù)a的取值范圍是__。
當a=0時,f(x)=x在區(qū)間
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上遞增;當
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時,f(x)是二次函數(shù),對稱軸為
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要使f(x)=ax
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+(1-3a)x+a在區(qū)間
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上遞增,需使
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解得:
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.綜上:實數(shù)a的取值范圍是 [0,1]。
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