A
分析:對于A,函數(shù)為奇函數(shù);根據(jù)y′=3x
2≥0,可知函數(shù)為增函數(shù);
對于B,函數(shù)是奇函數(shù),在(-∞,0)、(0,+∞)上單調(diào)減;
對于C,定義域為(0,+∞),非奇非偶;
對于D,根據(jù)
,可得函數(shù)為減函數(shù).
解答:對于A,∵(-x)
3=-x
3,∴函數(shù)為奇函數(shù);∵y′=3x
2≥0,∴函數(shù)為增函數(shù),即A正確;
對于B,函數(shù)是奇函數(shù),在(-∞,0)、(0,+∞)上單調(diào)減,即B不正確;
對于C,定義域為(0,+∞),非奇非偶,即C不正確;
對于D,∵
,∴函數(shù)為減函數(shù),即D不正確
故選A.
點評:本題考查函數(shù)的單調(diào)性與奇偶性,考查學(xué)生分析解決問題的能力,屬于中檔題.