分析:(1)先把左邊計(jì)算出來(lái)可得:0.6x=12,再利用等式的性質(zhì)兩邊同時(shí)除以0.6即可;
(2)根據(jù)比例的基本性質(zhì)可得:0.25x=0.125×8,再利用等式的性質(zhì),兩邊同時(shí)除以0.25即可;
(3)根據(jù)比例的基本性質(zhì)可得:2x=1.8×5,再根據(jù)等式的性質(zhì)兩邊同時(shí)除以2即可;
(4)根據(jù)等式的性質(zhì),兩邊同時(shí)減去1,再同時(shí)除以20%即可.
解答:解:(1)x-40%x=12,
0.6x=12,
0.6x÷0.6=12÷0.6,
x=20;
(2)x:8=0.125:0.25,
0.25x=0.125×8,
0.25x÷0.25=1÷0.25,
x=4;
(3)
=,
2x=1.8×5,
2x÷2=9÷2,
x=4.5;
(4)1+20%x=12.
1+20%x-1=12-1,
20%x=11,
20%x÷20%=11÷20%,
x=55.
點(diǎn)評(píng):此題考查了等式的性質(zhì)和比例的基本性質(zhì)的靈活應(yīng)用.