Question

孝感城區(qū)每天清晨都要進行灑水，若一輛灑水車空車質(zhì)量6t，水罐容積5m³.裝滿水后，車輪與地面的總接觸面積為0.5m².（ g 取10N/kg，ρ_水=1.0×10³kg/m³）。

問：

（1）該車最多能裝水的質(zhì)量為多少？

（2）灑完一半水時，灑水車對地面的壓強為多少？

（3）若罐內(nèi)水深1.5m，則水對罐底的壓強為多少？

Answer 1

（1）m=ρ_水V=1.0×10³kg/m³×5 m³=5×10³kg··························································· (1分)

（2）F=G_車+G_水=（6×10³+2.5×10³）kg×10N/kg=8.5×10⁴N····························· (1分)

P=F/S=8.5×10⁴N/0.5m²=1.7×10⁵Pa························································· (1分)

（3）P=ρ_水gh=1.0×10³kg/m³×10N/kg×1.5m=1.5×10⁴Pa···································· (1分)