Question

在一定質(zhì)量的某NaCl溶液中加入足量的AgNO₃溶液，所得AgCl沉淀質(zhì)量等于原NaCl溶液的質(zhì)量，則原NaCl溶液中溶質(zhì)的質(zhì)量分?jǐn)?shù)均為　．（計算結(jié)果保留到0.1%）                         

Answer 1

【考點】根據(jù)化學(xué)反應(yīng)方程式的計算；有關(guān)溶質(zhì)質(zhì)量分?jǐn)?shù)的簡單計算．         

【專題】溶質(zhì)質(zhì)量分?jǐn)?shù)與化學(xué)方程式相結(jié)合的計算．                     

【分析】氯化鈉和硝酸銀反應(yīng)生成氯化銀沉淀和硝酸鈉，根據(jù)氯化鈉溶液的質(zhì)量和氯化銀的質(zhì)量可以計算氯化鈉的質(zhì)量分?jǐn)?shù)．                                                        

【解答】解：設(shè)氯化鈉溶液的質(zhì)量為m，質(zhì)量分?jǐn)?shù)為x，                  

NaCl+AgNO₃═AgCl↓+NaNO₃，                                      

58.5       143.5                                            

mx           m                                              

=，                                              

x=40.8%，                                                   

故填：40.8%．                                               

【點評】本題主要考查學(xué)生運用假設(shè)法和化學(xué)方程式進行計算和推斷的能力，同時考查了分析數(shù)據(jù)的能力，計算時要注意規(guī)范性和準(zhǔn)確性．