4、下圖中圖一與圖二的內(nèi)在聯(lián)系是
圖一 列寧 圖二 阿芙樂(lè)爾號(hào)進(jìn)攻冬宮
A.列寧引導(dǎo)俄國(guó)人民取得十月革命的勝利
B.列寧親自指揮推翻了沙皇的專制統(tǒng)治
C.列寧領(lǐng)導(dǎo)俄國(guó)人民取得二月革命和十月革命的勝利
D.列寧領(lǐng)導(dǎo)俄國(guó)人民建成了世界上第一個(gè)社會(huì)主義國(guó)家
3、圖二是一枚為紀(jì)念俄國(guó)十月革命45周年而發(fā)行的郵票《攻打冬宮》。我們紀(jì)念十月革命的理由有:
①它建立樂(lè)世界上第一個(gè)社會(huì)主義國(guó)家
②它開(kāi)辟樂(lè)無(wú)產(chǎn)階級(jí)革命的新時(shí)代
③它是無(wú)產(chǎn)階級(jí)專政的第一次偉大嘗試
④它鼓舞和推動(dòng)了被壓迫民族的解放運(yùn)動(dòng)
A、①②③ B、①②④ C、①③④ D、②③④
2、有一段時(shí)期,明斯克生產(chǎn)的一粒紐扣在當(dāng)?shù)厥蹆r(jià)是1盧布,在700公里外的莫斯科售價(jià)也是1盧布,而在萬(wàn)里之外的海參崴售價(jià)仍是1盧布。這一時(shí)期應(yīng)該是
A.沙皇統(tǒng)治時(shí)期 B.戰(zhàn)時(shí)共產(chǎn)主義政策時(shí)期
C.新經(jīng)濟(jì)政策時(shí)期 D.斯大林體制時(shí)期
1、1920年,蘇俄農(nóng)民中流傳這樣的說(shuō)法:“土地屬于我們,面包卻屬于你們;水屬于我們,魚(yú)卻屬于你們;森林屬于我們,木材卻屬于你們”,這反映的是戰(zhàn)時(shí)共產(chǎn)主義政策( ) A.保障了農(nóng)民的利益 B.挫傷了農(nóng)民的積極性
C.實(shí)行了軍事化措施 D.取消了自由貿(mào)易制度
24. 解:(1)在上
.
反比例函數(shù)的解析式為:.······························· 1分
點(diǎn)在上
···················································································································· 2分
經(jīng)過(guò),,
解之得
一次函數(shù)的解析式為:············································································· 4分
(2)是直線與軸的交點(diǎn)
當(dāng)時(shí),
點(diǎn)……………………………………………5分
…………………………………………………………6分
8分
23.
解:(1)將點(diǎn)代入中,得k=9;
(2) 設(shè)Q點(diǎn)的縱坐標(biāo)為y,則,解得:y=4
將y=4,k=9代入中,得.Q
22.解:(1)設(shè)反比例函數(shù)關(guān)系式為,
反比例函數(shù)圖象經(jīng)過(guò)點(diǎn).
.···························································· 2分
反比例函數(shù)關(guān)第式.······························ 3分
(2)點(diǎn)在上,
.·················································································································· 5分
.················································································································ 6分
(3)示意圖.·············································································································· 8分
當(dāng)或時(shí),一次函數(shù)的值大于反比例函數(shù)的值.···································· 10分
21. 21.(1)∵ A(m,3)與B(n,2)關(guān)于直線y = x對(duì)稱,
∴ m = 2,n = 3, 即 A(2,3),B(3,2).
于是由 3 = k∕2,得 k = 6. 因此反比例函數(shù)的解析式為.
(2)設(shè)過(guò)B、D的直線的解析式為y = kx + b.
∴ 2 = 3k + b,且 -2 = 0 · k + b. 解得k =,b =-2.
故直線BD的解析式為 y =x-2.
∴ 當(dāng)y = 0時(shí),解得 x = 1.5.
即 C(1.5,0),于是 OC = 1.5,DO = 2.
在Rt△OCD中,DC =.
∴ sin∠DCO =.
說(shuō)明:過(guò)點(diǎn)B作BE⊥y軸于E,則 BE = 3,DE = 4,從而 BD = 5,sin∠DCO = sin∠DBE =.
20. 解:(1)設(shè)所求反比例函數(shù)的解析式為:.
點(diǎn)在此反比例函數(shù)的圖象上,
,.
故所求反比例函數(shù)的解析式為:.
(2)設(shè)直線的解析式為:.
點(diǎn)的反比例函數(shù)的圖象上,點(diǎn)的縱坐標(biāo)為1,設(shè),
,.
點(diǎn)的坐標(biāo)為.
由題意,得
解得:
直線的解析式為:.
19.
解:(1)解方程組得,
所以A、B兩點(diǎn)的坐標(biāo)分別為:A(1,1)、B(-1,-1)
(2)根據(jù)圖象知,當(dāng)或時(shí),正比例函數(shù)值大于反比例函數(shù)值
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