17. 解:設(shè)該文具廠原來(lái)每天加工這種文具套.
根據(jù)題意,列方程得,
解得
經(jīng)檢驗(yàn),是原方程的根.
答:該文具廠原來(lái)每天加工這種文具100套.
16. 解:設(shè)y=,則原方程可化為y-=-1, ∴ ∴=3,=-4當(dāng)=3時(shí), =3 ∴-3=0∴=-1,=3;當(dāng)=-4時(shí), =-4∴+4=0無(wú)解,經(jīng)檢驗(yàn)使原方程有意義∴原方程的解為=-1,=3
15. 化簡(jiǎn)得原式=,代入得=
14. 解:(1)設(shè)乙隊(duì)單獨(dú)完成這項(xiàng)工程需要x天,則甲隊(duì)單獨(dú)完成這項(xiàng)工程需要天.
根據(jù)題意,得
解得x=90.
經(jīng)檢驗(yàn),x=90是原方程的根. ……3分
∴
答:甲、乙兩隊(duì)單獨(dú)完成這項(xiàng)工程需要60天和90天. ……1分
(2)設(shè)甲、乙兩隊(duì)合作完成這項(xiàng)工程需要y天,則有
解得y=36. ……2分
需要施工費(fèi)用:36×(0.84+0.56)=50.4(萬(wàn)元). ……1分
∵50.4>50,
∴工程預(yù)算的施工費(fèi)用不夠用,需追加預(yù)算0.4萬(wàn)元. ……1分
13. 解:原式=2x-1+ ……4分
=2x-1+x+2
=3x+1 ……2分
12. 解:聰聰說(shuō)的有理.··························· 1分
······················· 3分
································· 4分
···································· 5分
只要使原式有意義,無(wú)論取何值,原式的值都相同,為常數(shù)1.········ 6分
11. 解:··························· 2分
··································· 5分
檢驗(yàn):將代入原方程,左邊右邊·················· 7分
所以是原方程的根··························· 8分
(將代入最簡(jiǎn)公分母檢驗(yàn)同樣給分)
10. 解 (Ⅰ)
|
速度(千米/時(shí)) |
所用時(shí)間(時(shí)) |
所走的路程(千米) |
騎自行車(chē) |
|
|
10 |
乘汽車(chē) |
|
|
10 |
················· 3分
(Ⅱ)根據(jù)題意,列方程得. ·················· 5分
解這個(gè)方程,得. ························· 7分
經(jīng)檢驗(yàn),是原方程的根.
所以,.
答:騎車(chē)同學(xué)的速度為每小時(shí)15千米. ···················· 8分
9. 解法一:原式················· 2分
·································· 6分
當(dāng)時(shí),原式························ 8分
解法二:原式············ 2分
·································· 6分
當(dāng)時(shí),原式························ 8分
8. 解法一:設(shè)乙班有人捐款,則甲班有人捐款.············ 1分
根據(jù)題意得:
······························ 5分
解這個(gè)方程得.···························· 8分
經(jīng)檢驗(yàn)是所列方程的根.························ 9分
(人)
答:甲班有48人捐款,乙班有45人捐款.·················· 10分
解法二:設(shè)甲班有人捐款,則乙班有人捐款.·············· 1分
根據(jù)題意得:
······························ 5分
解這個(gè)方程得.···························· 8分
經(jīng)檢驗(yàn)是所列方程的根.························ 9分
(人)
答:甲班有48人捐款,乙班有45人捐款.·················· 10分
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